A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
HOW DO I FIGURE THIS OUT \[6\sqrt{2}  3\sqrt{2}\]
anonymous
 4 years ago
HOW DO I FIGURE THIS OUT \[6\sqrt{2}  3\sqrt{2}\]

This Question is Closed

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1\[6\sqrt{2}  3\sqrt2 = \sqrt{2} \cdot (63) =3\sqrt2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do i do these? \[\sqrt{90} , \sqrt{125}, 4\sqrt{20}\]

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1What do you want to do with them? Just simplify them as much as possible?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no have an anser like \[9\sqrt{10} or 10\sqrt{9} examples\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This one i dont get either \[5\sqrt{10} * 3\sqrt{?}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i ment to put * \[3\sqrt{8}\]

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1Let's start with the first one.\[\sqrt{90} = \sqrt{9} \cdot \sqrt{10} = 3\sqrt{10}\]similarly, \[\sqrt{125} = \sqrt{25} \cdot \sqrt{5} = 5\sqrt5\]and\[4\sqrt{20} = 4\sqrt{4} \cdot \sqrt5 = 4 \cdot 2 \cdot \sqrt5 = 8\sqrt5\]

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1As for that last problem, \[5\sqrt{10} \cdot 3\sqrt8 = 15 \cdot \sqrt{10} \cdot \sqrt8 = 15 \cdot \sqrt{80}=15 \cdot \sqrt{16} \cdot \sqrt5 = 60\sqrt5\]Is it clear what you have to do for these problems now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont get the one i posted or the 4/20 one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would this one \[\sqrt{8} * \sqrt{3}\] = \[\sqrt{24}\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would this one \[\sqrt{8} * \sqrt{3}\] = \[\sqrt{24}\]?

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1That would be correct. Good job! As for the other problems, give me a few more seconds to finish typing up the response...

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1Well, both the 7/72 and 4/20 are basically the same problem with different numbers. You have an expression with some number outside the radical (4 and 7), and a number inside (20 and 72). At the beginning, you can just ignore the number outside. Then simplify the radical as much as possible. In this case, \[\sqrt{72} = \sqrt{36} \cdot \sqrt2 = 6\sqrt2\]and \[\sqrt{20} = \sqrt4 \cdot \sqrt5 =2\sqrt5\]Then, to finish it all off, you multiply by the number you originally had in front. So,\[7\sqrt{72}=7\cdot(6\sqrt2) = 42\sqrt2\]\[4\sqrt{20}=4\cdot (2\sqrt5)=8\sqrt5\]And those would be the final answers. Also, with the square root of 24, it would be better to then simplify like so\[\sqrt{24} = \sqrt4 \cdot \sqrt6 = 2\sqrt6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i see... ok. Thanks so much!

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.1Could you now simplify \[4\sqrt{45}\]just for a little bit more practice?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.