[Related Rates] Each side of a square is increasing at a rate of 6 cm/s. At what rate is the area of the square increasing when the area of the square is 16 cm^2?

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[Related Rates] Each side of a square is increasing at a rate of 6 cm/s. At what rate is the area of the square increasing when the area of the square is 16 cm^2?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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At a glance, this look accurate. But no guarantees; while since I have touched this.
Agent, do you have an answer to this?
Area= x^2 dx/dt=6 cm/s we have to find dA/dt when Area =16 or x=4 dA/dt=2x dx/dt dA/dt= 2*4*6 dA/dt=48 cm^2/sec area is increasing at the rate of 48cm^2/sec

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ooh..woops i thought the area was 64 lol

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