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|dw:1327468722698:dw| The figure is a right square. Solve for x.
so it would be (4x^2 + x - 37) * (-x^2 +x +43) right?
Sorry, I can't write with a mouse very well
You have to just multiply it all out. So start with the first term and multiply it. I'll get you started
Or, rather, use the distributive property
I do know that it is 4x^2+x-37=x^2+x+43 Is it?
sorry, I gave you the equation for area. Hold on. Do you know the area?
Yes, it is lw right?
is this how it was originally set up? I think we're missing some info
Sorry for the hassle! and this is all there is
You're right, it would be lw, but we have nothing to equal lw to!
It says: "The figure in the diagram is regular. Solve for x and find the perimeter."
regular meaning all angles and sides are congruent
You're right, set the two trinomials equal to each other! So Start with that
don't forget the (-) in front of x^2
4x^2+x-37=-x^2+x+43 And then I am stuck at this point
ok, well, add x^2 to both sides. what do you get?
add, not subtract
Oops, sorry! 5x^2+x-37=x+43
oK good. Now let's tackle the x terms. What should you do?
do they cancel out?
so what's next?
yep!! great job
divide by 5?
oh and x=4??
so what's the perimeter?
oh okay! Thanks so much, I really appreciate that you didn't leave me even though you wanted to go to bed and for helping me :)
is it correct?
I think you got it!
ok thanks again :) hope you have a good night!