One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at a rate of approximately 2.5% per year.
(a) Write the ratio of strontium-90 remaining, p , as a function of years, t , since the nuclear accident.

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- anonymous

- jamiebookeater

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- anonymous

p(t)=?

- A_clan

If p0 was the initial quantity, then
quantity after time t,
p(t) = p0 (e^ -kt)
The ratio of strontium remaining,p=
p(t)/p0 = (e^ -kt)
= (e^ -0.025t)

- anonymous

so it's just the last part? e^-....

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- A_clan

(e^ -0.025t)
This is required function

- anonymous

ok so p(t)= that

- A_clan

No p(t) = p0 (e^ -kt)
But the given problem is asking the ratio of Sr90 remaining,
So, p= p(t)/p0 is the solution

- anonymous

but it says p(t)=?

- A_clan

That is just a difference of naming convention.
If you want to call the ratio as p(t), then you can name
'the remaining quantity of Sr90' as , let us say 'pr'.
Then, P(t) = pr/p0 = (e^ -0.025t)

- anonymous

so its the e part i enter

- A_clan

yes the entire e part (exponential part)

- anonymous

okay thanks

- A_clan

np

- anonymous

Sorry, but i just entered e^....and it was wrong

- anonymous

ugh

- A_clan

There are different types of formula for the decay.
y=a(1-r)^t is also used.
try p(t)=(0.975)^t

- anonymous

but it simply says p(t)= what? so I dont know what to enter.

- anonymous

the e^... was wrong

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