anonymous
  • anonymous
One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at a rate of approximately 2.5% per year. (a) Write the ratio of strontium-90 remaining, p , as a function of years, t , since the nuclear accident.
Mathematics
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anonymous
  • anonymous
One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at a rate of approximately 2.5% per year. (a) Write the ratio of strontium-90 remaining, p , as a function of years, t , since the nuclear accident.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
p(t)=?
A_clan
  • A_clan
If p0 was the initial quantity, then quantity after time t, p(t) = p0 (e^ -kt) The ratio of strontium remaining,p= p(t)/p0 = (e^ -kt) = (e^ -0.025t)
anonymous
  • anonymous
so it's just the last part? e^-....

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A_clan
  • A_clan
(e^ -0.025t) This is required function
anonymous
  • anonymous
ok so p(t)= that
A_clan
  • A_clan
No p(t) = p0 (e^ -kt) But the given problem is asking the ratio of Sr90 remaining, So, p= p(t)/p0 is the solution
anonymous
  • anonymous
but it says p(t)=?
A_clan
  • A_clan
That is just a difference of naming convention. If you want to call the ratio as p(t), then you can name 'the remaining quantity of Sr90' as , let us say 'pr'. Then, P(t) = pr/p0 = (e^ -0.025t)
anonymous
  • anonymous
so its the e part i enter
A_clan
  • A_clan
yes the entire e part (exponential part)
anonymous
  • anonymous
okay thanks
A_clan
  • A_clan
np
anonymous
  • anonymous
Sorry, but i just entered e^....and it was wrong
anonymous
  • anonymous
ugh
A_clan
  • A_clan
There are different types of formula for the decay. y=a(1-r)^t is also used. try p(t)=(0.975)^t
anonymous
  • anonymous
but it simply says p(t)= what? so I dont know what to enter.
anonymous
  • anonymous
the e^... was wrong

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