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anonymous

  • 4 years ago

One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at a rate of approximately 2.5% per year. (a) Write the ratio of strontium-90 remaining, p , as a function of years, t , since the nuclear accident.

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  1. anonymous
    • 4 years ago
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    p(t)=?

  2. A_clan
    • 4 years ago
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    If p0 was the initial quantity, then quantity after time t, p(t) = p0 (e^ -kt) The ratio of strontium remaining,p= p(t)/p0 = (e^ -kt) = (e^ -0.025t)

  3. anonymous
    • 4 years ago
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    so it's just the last part? e^-....

  4. A_clan
    • 4 years ago
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    (e^ -0.025t) This is required function

  5. anonymous
    • 4 years ago
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    ok so p(t)= that

  6. A_clan
    • 4 years ago
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    No p(t) = p0 (e^ -kt) But the given problem is asking the ratio of Sr90 remaining, So, p= p(t)/p0 is the solution

  7. anonymous
    • 4 years ago
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    but it says p(t)=?

  8. A_clan
    • 4 years ago
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    That is just a difference of naming convention. If you want to call the ratio as p(t), then you can name 'the remaining quantity of Sr90' as , let us say 'pr'. Then, P(t) = pr/p0 = (e^ -0.025t)

  9. anonymous
    • 4 years ago
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    so its the e part i enter

  10. A_clan
    • 4 years ago
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    yes the entire e part (exponential part)

  11. anonymous
    • 4 years ago
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    okay thanks

  12. A_clan
    • 4 years ago
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    np

  13. anonymous
    • 4 years ago
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    Sorry, but i just entered e^....and it was wrong

  14. anonymous
    • 4 years ago
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    ugh

  15. A_clan
    • 4 years ago
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    There are different types of formula for the decay. y=a(1-r)^t is also used. try p(t)=(0.975)^t

  16. anonymous
    • 4 years ago
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    but it simply says p(t)= what? so I dont know what to enter.

  17. anonymous
    • 4 years ago
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    the e^... was wrong

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