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get the equation= to zero soo subtract both sides by 2x^2
wait so how do u factor that?
@ marie the factorization is incorrect x = 1/2(1 plus-minus root 3)
oh opps lol thanksand the last step is factoring
like im really bad at factoring....can u show me how?
I'm gonna use square root factoring...... I can give you anohter example to factor unless you need to factor for this equation
Actually this equation becomes a little ugly when we try to factor it, so instead we can use the quadratic equation formula.
a+or- squareroot of b^2-(a*c) all divided by 2a
well im suppose to factor it...maybe the quadratic equation would work though.....i have to have a smaller and larger value of x
if you are supposed to have two differnt answers of x then I would go for quadratic formula
All right the factors are [x - (1+root3)/2][x - (1-root3)/2]
so how would u find x through that?
idk about Aron's way but here's how I would do it. a=-27 b=2 c=1 x= -27+or- squareroot4(-27) all divided by 2(-27)
the two answers come from one solving for just negative the other solving for just positive
Just set it equal to 0;the factors [x - (1+root3)/2][x - (1-root3)/2]