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anonymous

  • 4 years ago

solve the equation any way. 2x^2=2x+1 :)

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  1. anonymous
    • 4 years ago
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    get the equation= to zero soo subtract both sides by 2x^2

  2. anonymous
    • 4 years ago
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    now factor

  3. anonymous
    • 4 years ago
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    (2x+1)(1x+1)

  4. anonymous
    • 4 years ago
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    wait so how do u factor that?

  5. anonymous
    • 4 years ago
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    @ marie the factorization is incorrect x = 1/2(1 plus-minus root 3)

  6. anonymous
    • 4 years ago
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    oh opps lol thanksand the last step is factoring

  7. anonymous
    • 4 years ago
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    like im really bad at factoring....can u show me how?

  8. anonymous
    • 4 years ago
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    I'm gonna use square root factoring...... I can give you anohter example to factor unless you need to factor for this equation

  9. anonymous
    • 4 years ago
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    Actually this equation becomes a little ugly when we try to factor it, so instead we can use the quadratic equation formula.

  10. anonymous
    • 4 years ago
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    a+or- squareroot of b^2-(a*c) all divided by 2a

  11. anonymous
    • 4 years ago
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    well im suppose to factor it...maybe the quadratic equation would work though.....i have to have a smaller and larger value of x

  12. anonymous
    • 4 years ago
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    if you are supposed to have two differnt answers of x then I would go for quadratic formula

  13. anonymous
    • 4 years ago
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    All right the factors are [x - (1+root3)/2][x - (1-root3)/2]

  14. anonymous
    • 4 years ago
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    so how would u find x through that?

  15. anonymous
    • 4 years ago
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    idk about Aron's way but here's how I would do it. a=-27 b=2 c=1 x= -27+or- squareroot4(-27) all divided by 2(-27)

  16. anonymous
    • 4 years ago
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    the two answers come from one solving for just negative the other solving for just positive

  17. anonymous
    • 4 years ago
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    Just set it equal to 0;the factors [x - (1+root3)/2][x - (1-root3)/2]

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spraguer (Moderator)
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