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anonymous
 4 years ago
Use the Law of Levers to solve the problem, x1y1 = x2y2. A rectangle has a length of 50 inches and a width of 20 inches. What is the length of another rectangle of the same area, if it has a width of 25 inches?
62.5 in
10 in
30 in
40 in
anonymous
 4 years ago
Use the Law of Levers to solve the problem, x1y1 = x2y2. A rectangle has a length of 50 inches and a width of 20 inches. What is the length of another rectangle of the same area, if it has a width of 25 inches? 62.5 in 10 in 30 in 40 in

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use the Law of Levers to solve the problem, x1y1 = x2y2. Milly's older brother weighs 90 pounds and sits 2.5 feet away from the fulcrum of a seesaw. Milly sits 4 feet away and the seesaw balances. About how many pounds does Milly weigh? 60.5 lb 56.25 lb 64.25 lb 52.5 lb
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