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tux

  • 4 years ago

Evaluate integral: 1/(x+sqrt(x))

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  1. nikvist
    • 4 years ago
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    \[\int\frac{dx}{x+\sqrt{x}}=\int\frac{dx}{\sqrt{x}(\sqrt{x}+1)}\quad;\quad y=\sqrt{x}\quad,\quad dy=\frac{dx}{2\sqrt{x}}\]\[=2\int\frac{dy}{y+1}=2\ln{(y+1)}+C=2\ln{(\sqrt{x}+1)}+C\]

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