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anonymous
 4 years ago
How to solve this integral:
anonymous
 4 years ago
How to solve this integral:

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}1/(1x ^{2})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what does that long thing before the first one mean?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hint:x=sinu....dx=cosu.du

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SKforlife: It's the symbol for integral equations :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0integ_(cosu.du/1sin^2(u))=integ_cosudu/cos^2(u)=integ_du/cosu=integ_secu.du integ_secu.du=ln(secu+tanu) draw a triangle..your angle is u..sinu=x then write each other.

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1i\[=\int\limits{\frac{1}{(1x)(1+x)}dx}\]break intp partial fractions\[\frac{1}{(1x)(1+x)}=\frac{A}{1x}+\frac{B}{1+x}\]

nikvist
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{1}{1x^2}=\frac{1}{2}\left(\frac{1}{1x}+\frac{1}{1+x}\right)\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.1yeah what nikvist did xD
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