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anonymous

  • 4 years ago

How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) What is the correct question to solve this problem?

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  1. anonymous
    • 4 years ago
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    add 6 L

  2. anonymous
    • 4 years ago
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    10.8/18

  3. ash2326
    • 4 years ago
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    let the amount added be x litres 12 L of a 40 % solution has 4.8 litres of antifreeze (4.8+x)/ (12+x) *100=60 4.8+x=0.6(12+x) 4.8+x=7.2+0.6x 0.4x=2.4 x=6 litres

  4. anonymous
    • 4 years ago
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    6 litres

  5. Hero
    • 4 years ago
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    x + 12 = y x + .40(12) = .60y

  6. Hero
    • 4 years ago
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    Satellite, congratulations on getting 10,000 medals

  7. anonymous
    • 4 years ago
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    \[.4\times 12+x=.6(12+x)\] solve for x thank you!!!

  8. anonymous
    • 4 years ago
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    Wow, that's cool! 10000 medals!!!

  9. anonymous
    • 4 years ago
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    kind of silly, huh?

  10. Hero
    • 4 years ago
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    Yup. You're officially the Godfather of OS

  11. anonymous
    • 4 years ago
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    What's silly?

  12. anonymous
    • 4 years ago
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    yeah, but haven't moved up a level since august

  13. Hero
    • 4 years ago
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    lol

  14. anonymous
    • 4 years ago
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    You can't right?

  15. anonymous
    • 4 years ago
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    really. i think it is impossible. no matter though.

  16. anonymous
    • 4 years ago
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    For users who are below lvl 100, the bar on the right corner shows how far you are from the next lvl. What does it look like when you're lvl 100? Can you post the picture satellite, just curious.....

  17. anonymous
    • 4 years ago
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    satellite do you work here? How long has it taken you to get so many medals?!

  18. anonymous
    • 4 years ago
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    He's not a mod....

  19. Hero
    • 4 years ago
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    Satellite was here before OS was OS as we know it.

  20. anonymous
    • 4 years ago
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    Satellite, can you post the pic please....

  21. Hero
    • 4 years ago
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    Where's muffin?

  22. anonymous
    • 4 years ago
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    What muffin?

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spraguer (Moderator)
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