## anonymous 4 years ago How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) What is the correct question to solve this problem?

1. anonymous

2. anonymous

10.8/18

3. ash2326

let the amount added be x litres 12 L of a 40 % solution has 4.8 litres of antifreeze (4.8+x)/ (12+x) *100=60 4.8+x=0.6(12+x) 4.8+x=7.2+0.6x 0.4x=2.4 x=6 litres

4. anonymous

6 litres

5. Hero

x + 12 = y x + .40(12) = .60y

6. Hero

Satellite, congratulations on getting 10,000 medals

7. anonymous

$.4\times 12+x=.6(12+x)$ solve for x thank you!!!

8. anonymous

Wow, that's cool! 10000 medals!!!

9. anonymous

kind of silly, huh?

10. Hero

Yup. You're officially the Godfather of OS

11. anonymous

What's silly?

12. anonymous

yeah, but haven't moved up a level since august

13. Hero

lol

14. anonymous

You can't right?

15. anonymous

really. i think it is impossible. no matter though.

16. anonymous

For users who are below lvl 100, the bar on the right corner shows how far you are from the next lvl. What does it look like when you're lvl 100? Can you post the picture satellite, just curious.....

17. anonymous

satellite do you work here? How long has it taken you to get so many medals?!

18. anonymous

He's not a mod....

19. Hero

Satellite was here before OS was OS as we know it.

20. anonymous

Satellite, can you post the pic please....

21. Hero

Where's muffin?

22. anonymous

What muffin?