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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
 2 years ago
 2 years ago
Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
 2 years ago
 2 years ago

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mark_o.Best ResponseYou've already chosen the best response.0
3x + y = 7 y=3x+7 here slope m = 3 the line perpendicular has slope m=1/m=1/(3)=1/3 now at point(6,1)=(x1,y1) from yy1=m(xx1) we get y(1)=(1/3)(x6) y+1 = (1/3)x 2 y= (1/3)x 21=(1/3)x3
 2 years ago

amistre64Best ResponseYou've already chosen the best response.0
SWAP COEFFS AND NEGATE ONE Of em ..... bad pinky!! 3x+y = 7 x3y = 7 , that sevens from something other than what we want so delete in and find a new constant x3y = c the given point has to fit ...
 2 years ago
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