Last year, McBarkie's Burgers contained 200 grams of fat in each burger. This year, the amount of fat has been reduced to 120 grams per burger. What is the percent of decrease in the number of grams of fat per burger to the nearest percent?

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Last year, McBarkie's Burgers contained 200 grams of fat in each burger. This year, the amount of fat has been reduced to 120 grams per burger. What is the percent of decrease in the number of grams of fat per burger to the nearest percent?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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80/200 * 100 = 40% decrease.
40 %
The general formula for percent decrease is: \[\%\Delta = \frac{|a - b|}{a} \times 100\] , where a = original amount and b = new amount. In this case, a = 200, b = 120 And 40% decrease is correct.

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Actually, that's the formula for percent increase or decrease
Yes.

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