anonymous
  • anonymous
What is the third perfect number? Please help me understand how it works. thnx
Mathematics
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schrodinger
  • schrodinger
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Hero
  • Hero
1^2 = 1 2^2 = 4 3^2 = 9 The third perfect number is 9? Did you mean perfect SQUARES?
anonymous
  • anonymous
ohh, no, ummm, like the first number is 6, the second is 28, and idk what the third is...plus idk how to get the number
anonymous
  • anonymous
Aperfect number is a positive integer that is equal to the sum of its proper positive divisors. Mathematically, \( \sigma_1(N)=2N \) \(\sigma_1() \) is the divisor function (http://en.wikipedia.org/wiki/Divisor_function) Here is the list of perfect numbers in OEIS: http://oeis.org/A000396

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Hero
  • Hero
Never heard of it
Hero
  • Hero
And fool clearly wiki'd it
anonymous
  • anonymous
A year back I wrote a very optimized perfect number generator.
anonymous
  • anonymous
whoa, did you code it all?
anonymous
  • anonymous
Unfortunately it's a part of an algorithm contest, so I can't share the code here. But I can give some hints if you want :)
anonymous
  • anonymous
Hero, I don't really need to wike perfect numbers :)
anonymous
  • anonymous
Yes please, any that are available :) I just started coding a few days ago and I'm working through the Python textbook. Just started my first more complex code (finding slope and y-intercept)still very simple, but I'd appreciate it
anonymous
  • anonymous
Okay first there are no odd perfect numbers (this is not proven yet) so you can clearly ignore the odd numbers.
anonymous
  • anonymous
ok
Hero
  • Hero
Why am I just now hearing about perfect numbers? In what course do you usually learn about them?
Hero
  • Hero
14yamaka, what course are you currently taking?
anonymous
  • anonymous
Now, you need to have a very fast \( \sigma_1(N) \) for that you need to have a fast optimized prime generator. This is actually deep I have used Miller Rabin algorithm.
anonymous
  • anonymous
@Hero: Elementary Number theory.
anonymous
  • anonymous
14yamaka, I would probably advice you to be satisfied with typical brute-force at this stage :)
anonymous
  • anonymous
*This is actually deep, I have used Miller Rabin algorithm + sieve.
anonymous
  • anonymous
wow, ok, I gotta read up on this Miller Rabin algorithm. and sieve. Thanks for the explanation. Both of you :)
anonymous
  • anonymous
Fain I help :)
Hero
  • Hero
I didn't provide anything, lol FFM provided everything

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