anonymous
  • anonymous
Calculate the number of moles in 0.457 grams of NaCl, sodium chloride.
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
0.0078
anonymous
  • anonymous
Explain why the number you calculated for Avogadro’s number may not match theactual number of 6.02 x 10^23
ash2326
  • ash2326
atomic mass of Na Cl= 23.5+35=58.5 amu 1 mole weighs 58.5 gm so 1 gram has 1/58.5 moles 0.457gm will have 0.457/58.5=0.0078 moles

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ash2326
  • ash2326
1 mole contains 6.023*10^23 molecules here we have 0.0078 moles so 0.0078*6.023*10^23= 4.6974*10^6 mlecules
anonymous
  • anonymous
\[n=M/M _{a}\] n=0.457/(23+35)=7.9*10^(-3)
ash2326
  • ash2326
Hayat Cakes, next time post chemistry questions in chemistry group. Moderator can delete your post.
anonymous
  • anonymous
oh okay thanks.
ash2326
  • ash2326
anyways, did you get the problem

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