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anonymous
 4 years ago
solve 2secx+tanx=3 on the interval xE[0,2pi]
anonymous
 4 years ago
solve 2secx+tanx=3 on the interval xE[0,2pi]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we have \[\frac{2}{\cos(x)}+\frac{\sin(x)}{\cos(x)}=\frac{2+\sin(x)}{\cos(x)}=3\] so \[2+\sin(x)=3\cos(x)\] \[3\cos(x)\sin(x)=2\] \

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now we have to write \[3\cos(x)\sin(x)\] as a single function of sine, we get something like \[\sqrt{10}\sin(x+\tan^{1}(3))\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{10}\sin(x\tan^{1}(3))=2\] i think it is right now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i wonder if there is an easier way, but i don't see it. you can divide by \[\sqrt{10}\]and take the inverse sine of the result

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let me try something else

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no just going around in circles. the above will do it. do you have another method you are supposed to use?
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