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Use equation,
E=F/q

what i have is
\[E=1/(4\pi \epsilon _{0}) * Q/r^{2}\]

but you don't have charge. so you can't use this relation.

\[Q=L \lambda\]
and the prof said use 2 for L. not sure why, maybe 10cm/5cm but why do that?

did you got?

why L=2?? may be due to doubling the length.

not really, i can't recall how to solve for force. force of field on wire or vice versa?

or are you saying solve for force after i find E?

ok follow me.

alright

use 1 equation and find Q by substituting values,
k=9*10^9
E=2000
r=0.05m

right

Q=5.56*10^-10

ok good.
Now use equation 2 and find F.
by substituting values of,
E=2000
q=5.56*10^-10

should be 1.11*10^-6

you are welcome.

hey jamesj who is this person who is reviewing 3rd question of emcrazy14?

thx, i had my r squared, should be able to get it now