anonymous
  • anonymous
if i could some assistance with this problem that would be great...
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
if i could some assistance with this problem that would be great...
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
4 (l'hospitals rule)
anonymous
  • anonymous
thank you very much
1 Attachment

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
you tried it and it worked out?
anonymous
  • anonymous
we havnt done hospitals rule yet,and i looked it yup and you take the derivative of that of both functions right?
1 Attachment
anonymous
  • anonymous
yeah...take derivative of top and bottom separetly. use the same limit and evaluate. if it still tends to infinity then you can rinse repeat until it converges to a limit
anonymous
  • anonymous
okay im still very new to derivatives(we learned them slightly in physics) but the the derivative of the function X-1 equals 0 because the derivative of the x=1 and if i rewrite the bottom as (x-3)^-1/2 and take the take the derivative of that i get 2(x-3)^2-1 which i simplify to 2(x-3)^-1 and the i plug in my limit value which gives me 1/4^-1 or 4. is that all correct?
1 Attachment
anonymous
  • anonymous
yep thats what i did
1 Attachment
anonymous
  • anonymous
thank you very much
1 Attachment
anonymous
  • anonymous
See if you can follow this...previous scan cut off
anonymous
  • anonymous
i could follow it thanks so much
1 Attachment
anonymous
  • anonymous
im assuming i will start understanding them when i we start talking about them in calc because we will go in depth with them, in physics we spent one day on them
1 Attachment
anonymous
  • anonymous
Yeah, usually get into limits when your learning the fundamentals of calculus. it's usually anything but exciting when your doing limits. good luck

Looking for something else?

Not the answer you are looking for? Search for more explanations.