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anonymous

  • 4 years ago

Identical point charges Q are placed at each of the four corners of a rectangle measuring 2.03 m by 3.39 m. If Q = 34.9 μC, what is the magnitude of the electrostatic force on any one of the charges?

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  1. JamesJ
    • 4 years ago
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    You here?

  2. anonymous
    • 4 years ago
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    I am, working between my HW site and here

  3. JamesJ
    • 4 years ago
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    Start with a diagram, like this one:

  4. JamesJ
    • 4 years ago
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    Now, write \( F_{12} \) for the force of charge \( Q_2 \) on \( Q_1 \). By Coulomb's law it is \[ F_{12} = \frac{Q_1Q_2}{4 \pi \epsilon_0 d_{12}^2 } \]

  5. anonymous
    • 4 years ago
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    OK, I have a drawing and labelled. In the formula, is that the equivalent of kQ1Q2/r^2

  6. JamesJ
    • 4 years ago
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    Now \( F_{12} \) is in the negative y direction; \( F_{14} \) is in the positive x direction; and \( F_{13} \) in the diagonal direction given. Write all of that out in vector notation and then find the magnitude of the sum of the three vectors. Then by symmetry, the magnitude of the charge on the other three points is the same.

  7. JamesJ
    • 4 years ago
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    **magnitude of the _force_ on the other ... [not charge]

  8. anonymous
    • 4 years ago
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    OK I am going to try to work on it and see what I can find my answer, I may be back.

  9. JamesJ
    • 4 years ago
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    It's a bit of computational pain.

  10. anonymous
    • 4 years ago
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    I can tell.

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