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anonymous
 4 years ago
how would you write a=p+p+prt for t
anonymous
 4 years ago
how would you write a=p+p+prt for t

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0she want me to show step by step

ChrisS
 4 years ago
Best ResponseYou've already chosen the best response.0so combine the p's first so you have a=2p+prt then subtract 2p from both sides to get a2p=prt then divde pr from both sides which isolates t and gives the solution in my first post.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you chrisS so i write it like that i sould get a passing grade

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have one more you think you can show me how to write it step by steo

ChrisS
 4 years ago
Best ResponseYou've already chosen the best response.0written out it will look like this a=p+p+prt a=2p+prt a2p=prt \[\frac{a2p}{pr}=t\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the perimeter of a rectangle is 120 centimeters the length of the rectangleis four less than three times the width. what are the dimensions of the rectangle

ChrisS
 4 years ago
Best ResponseYou've already chosen the best response.0Alright so your perimeter is the sum of the sides or 2 times the length plus two times the width or 2l+2w. You haven't been given either but you've been given a way to define the length in terms of the width. The length is four less than three times the width or l=3w4 You have been given the actual perimeter of the rectangle, so your original formula is 2l+2w=120 Since you've defined l in terms of w, you just plug that formula (3w4) in for l so you get 2(3w4)+2w=120 then factor to 2 into the 3w4 6w8+2w=120 combine like terms 8w8=120 then just algebra 8w=128 w=16 then plug 16 into the formula you derived for l l=3w4 l=3(16)4 l=484 l=44 so your width is 16 and your length is 44 and to check it, you should get 120 if you add those together and multiply by 2.
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