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\[\frac{a.b}{|a|^2}a\]

wow u did that really quickly

just got out of calc3 that just went over it :)

in the numerator...is that a times b?

a dot b

a dot b divided by magnitude of a squared all multiplied by a?

yes, the left side is a scalar; and the right side is vector a scaled to that length

would it be a bother to run me through how u got to this expression?

|dw:1327527260794:dw|

|b| cos(t) = the length of Ab, if we use your notation for proj{a} b

\[|b|cos(t) =|b| \frac{a.b}{|a||b|}=\frac{a.b}{|a|}\]
good so far?

yea i get that

i'm with u

i'm also trying to decode your picture :)

is that the x coordinate down there at the end?

the long vector

\[\frac{a.b}{|a|}\ \frac{a}{|a|}=; unit\ a, scaled\ by\ needed\ length\]

okay

and since |a| |a| = |a|^2 i just condensed it alittle bit

simple enough?

|dw:1327527605851:dw|

can u redraw that picture from above?

oh okay now i see

lol, i cant draw on this thing very well period :)

okay....so that's it for the equation now?

and what u first initally gave me is that correct?

yes, seeing how that is what we ended up with in the end i would say that its correct :)

u are an absolute life saver

thnx, good luck :)