the symbol\[A _{b}\] stands for the projection of vector A onto vector B. In other words, \[A _{b}\] represents the component of A that is parallel to B. Derive an expression for \[A _{b}\] in terms of the vectors A and B.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

the symbol\[A _{b}\] stands for the projection of vector A onto vector B. In other words, \[A _{b}\] represents the component of A that is parallel to B. Derive an expression for \[A _{b}\] in terms of the vectors A and B.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\frac{a.b}{|a|^2}a\]
wow u did that really quickly
just got out of calc3 that just went over it :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

in the numerator...is that a times b?
a dot b
a dot b divided by magnitude of a squared all multiplied by a?
yes, the left side is a scalar; and the right side is vector a scaled to that length
would it be a bother to run me through how u got to this expression?
|dw:1327527260794:dw|
|b| cos(t) = the length of Ab, if we use your notation for proj{a} b
\[|b|cos(t) =|b| \frac{a.b}{|a||b|}=\frac{a.b}{|a|}\] good so far?
yea i get that
i'm with u
i'm also trying to decode your picture :)
is that the x coordinate down there at the end?
the long vector
now, we need to scale that to a unit vector of a; since a is |a| long, lets divide it by |a| to get it to a length of 1
\[\frac{a.b}{|a|}\ \frac{a}{|a|}=; unit\ a, scaled\ by\ needed\ length\]
okay
and since |a| |a| = |a|^2 i just condensed it alittle bit
simple enough?
|dw:1327527605851:dw|
can u redraw that picture from above?
oh okay now i see
lol, i cant draw on this thing very well period :)
okay....so that's it for the equation now?
to find the the vector that is the proj of b onto a; yes; reduce a to ints unit equivalent; and scale it up by the magnitude of b*cos(t)
and what u first initally gave me is that correct?
yes, seeing how that is what we ended up with in the end i would say that its correct :)
u are an absolute life saver
thnx, good luck :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question