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anonymous
 4 years ago
I don't even know where to begin at, let alone understand how to do this....
Test the following equation for symmetry. Show all work. x=y^26
anonymous
 4 years ago
I don't even know where to begin at, let alone understand how to do this.... Test the following equation for symmetry. Show all work. x=y^26

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0f(y) = f(y), its even; f(y) = f(y) its odd; if neither of those then its neither

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.2first replace y with y: x = (y)^2  6 this is the same as x = y^2  6 so the graph is symmetrical about the x  axis

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.2if we try replacing x with x the above is not found so not symmetrical about yaxis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0easy pick a yvalue, say y = 2, then use the neg, y=2 now see if they give you the same x value x = 2^2 6 = 2 x = (2)^2 6 = 2
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