For the following function find the vertical, horizontal, and oblique asymptotes, if any
f(x)= -23x^2/2x^2-3x^2-18x +27
Stacey Warren - Expert brainly.com
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is that supposed to be 2x^3 in denominator ?
since the degree in denominator is greater, the horizontal asymptote is y=0
and there are no oblique
to find the vertical asymptotes, set the denominator equal to zero and solve for x
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you may be able to solve it using factor by grouping
were you able to factor the denominator?
im so confused
(2x^3 -3x^2) +(-18x+27)
factor each group
1st group has a x^2 in common
2nd group has a -9 in common
--> x^2(2x -3) -9(2x-3)
Notice the terms inside parenthesis are the same, so factor them out
--> (2x-3)(x^2 -9)
so would this be my answer
no you are finding the vertical asymptotes right....so your answer will be
x = ?
take whats above and set it equal to 0
how would i set it to equal 0
put a "=0" after it ??
ok i did that
solve for x:
2x-3 = 0
x^2 -9 = 0
ok what do i have to do now
solve the 2 equations...this is algebra, get x by itself
if you're taking a class where you have to find asymptotes and evaluate functions, im assuming you know how to solve simple algebraic equations