anonymous
  • anonymous
What is the sum of a 6–term geometric series if the first term is 21 and the last term is 1,240,029?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
sum = a(1-r^n)/(1-r) http://en.wikipedia.org/wiki/Geometric_series. solve.
anonymous
  • anonymous
????
cwrw238
  • cwrw238
in ronncc's formula a = first term = 21, n = 6 (number of terms), and r = common ratio

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anonymous
  • anonymous
is it 1527890?
cwrw238
  • cwrw238
the terms or of the form a, ar , ar^2, ar^3 ..... 6th term = ar^5 r^5 = 6th term / first term r^5 = 1,240,029 / 21 = 59049 r = 9 so plug these values into the formula: sum = 21 * 9^6 - 1 ------ = 6 - 1
cwrw238
  • cwrw238
= 2232048
cwrw238
  • cwrw238
where are you van??

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