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anonymous
 4 years ago
36.0kn/c=2(8.99x10^9)(Q/2.59)/.197
solve for Q
anonymous
 4 years ago
36.0kn/c=2(8.99x10^9)(Q/2.59)/.197 solve for Q

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1The right hand side, RHS is \[ RHS = 2(8.99 \times 10^9)(Q/2.59)/.197 \] \[ = (3.524 \times 10^{10})Q \] \[ = \frac{36.0kn}{c} = LHS \] Now it should be easier for you.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1ok ... hope that helped. find me or someone in Physics chat if you need more help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just didn't know how to deal with the Q/2.59

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1yes ... just put the 2.59 and the 0.197 in the denominator.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what did you get as a final answer.. just to compare and make sure i did it right

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1I didn't calculate the final answer, but it's obviously Q = (some constant, of order 9 or so)*(kn/c)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks man.. some one that finally helped me and didn't start spittin out more complicated formulas

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1sure. Come back soon with some more Physics questions.
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