## anonymous 4 years ago 36.0kn/c=2(8.99x10^9)(Q/2.59)/.197 solve for Q

1. JamesJ

The right hand side, RHS is $RHS = 2(8.99 \times 10^9)(Q/2.59)/.197$ $= (3.524 \times 10^{10})Q$ $= \frac{36.0kn}{c} = LHS$ Now it should be easier for you.

2. JamesJ

Yes?

3. JamesJ

chan ... talk to me

4. JamesJ

ok ... hope that helped. find me or someone in Physics chat if you need more help

5. anonymous

i just didn't know how to deal with the Q/2.59

6. JamesJ

yes ... just put the 2.59 and the 0.197 in the denominator.

7. anonymous

so what did you get as a final answer.. just to compare and make sure i did it right

8. JamesJ

I didn't calculate the final answer, but it's obviously Q = (some constant, of order -9 or so)*(kn/c)

9. anonymous

thanks man.. some one that finally helped me and didn't start spittin out more complicated formulas

10. JamesJ

sure. Come back soon with some more Physics questions.