## anonymous 4 years ago If h(t) represents the height of an object above ground level at time t and h(t) is given by: h(t)=-16t^2+14t+1 find the speed at time t=0.

1. anonymous

this is physics. use that forum.

2. anonymous

im learning this in calculus

3. anonymous

oh cool. calc AB or BC. that determines how to do this.

4. anonymous

idk. its my first calc class. its the intro course.

5. anonymous

uhhh... do you know how to differentiate? or take limits?

6. anonymous

we just started doing that in class. not too keen on it yet.

7. anonymous

ok so the derivative of position is velocity because the "change" in position is velocity. so differentiate h(x)

8. anonymous

i dont know what it means to differentiate

9. anonymous

i thought you just plug in for T?

10. anonymous

ok do you know how to: 1) take a derivative 2) find a limit? which one do you know...basically what are you doing in class now?

11. anonymous

we just started derivatives and limits... we've mainly been doing rate of change where you plug in something in the function.

12. anonymous

eh. you have to take the derivative of that.. or just use the limit definition of the derivative to take the derivative...you need to do one.

13. anonymous

can you show me how to do that?

14. anonymous

v(t) = dh/dt = -32t + 14

15. anonymous

v(0) = 0 + 14

16. anonymous

17. anonymous

ok so the derivative of something is taking the 2 from the square and multiplying it by the coefficient... what happened to the +1 at the end of the function?

18. phi

derivative of a constant = 0

19. phi

think of it as 1*t^0

20. anonymous

|dw:1327531319590:dw|

21. anonymous

|dw:1327531370597:dw|

22. anonymous

cant i just multiply whatever the coefficient is by 2 and then plug in the last number for T or whatever other letter and get the right answer every time?

23. anonymous

|dw:1327531709121:dw|

24. anonymous

and then plug zero for the first T of course to get the right answer