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anonymous
 4 years ago
If h(t) represents the height of an object above ground level at time t and h(t) is given by: h(t)=16t^2+14t+1
find the speed at time t=0.
anonymous
 4 years ago
If h(t) represents the height of an object above ground level at time t and h(t) is given by: h(t)=16t^2+14t+1 find the speed at time t=0.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is physics. use that forum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im learning this in calculus

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh cool. calc AB or BC. that determines how to do this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk. its my first calc class. its the intro course.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0uhhh... do you know how to differentiate? or take limits?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we just started doing that in class. not too keen on it yet.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so the derivative of position is velocity because the "change" in position is velocity. so differentiate h(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont know what it means to differentiate

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i thought you just plug in for T?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok do you know how to: 1) take a derivative 2) find a limit? which one do you know...basically what are you doing in class now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we just started derivatives and limits... we've mainly been doing rate of change where you plug in something in the function.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0eh. you have to take the derivative of that.. or just use the limit definition of the derivative to take the derivative...you need to do one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you show me how to do that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0v(t) = dh/dt = 32t + 14

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Therefore , Answer = 14

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so the derivative of something is taking the 2 from the square and multiplying it by the coefficient... what happened to the +1 at the end of the function?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0derivative of a constant = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327531319590:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327531370597:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cant i just multiply whatever the coefficient is by 2 and then plug in the last number for T or whatever other letter and get the right answer every time?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327531709121:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and then plug zero for the first T of course to get the right answer
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