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anonymous
 4 years ago
Does anyone know how to compute these following combinations?
1. C(6,4)
2. C(7,5)
3. C(9,6)
4. C(8,2) x C(8,6)
anonymous
 4 years ago
Does anyone know how to compute these following combinations? 1. C(6,4) 2. C(7,5) 3. C(9,6) 4. C(8,2) x C(8,6)

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campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1the formula is \[nCr = (n!)/((r!)\times(nr)!)\] \[6C4 = 6!/((4!)\times(64)!)\] You should have a calculator function that does it for you....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea but we cant use calculators for the test

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1its factorial notation (6x5x4x3x2x1)/((4x3x2x1)x(2x1)) cancel common factors and you'll be left with 3 x 5 = 15

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why the 2x1 at the end of the equation come from

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1because the formula says (nr)! this is 6  4)! or (2)!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thank you very much
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