A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Find the net electric flux through the spherical closed surface shown in the figure below. The two charges on the right are inside the spherical surface. (Take q1 = +1.84 nC, q2 = +1.02 nC, and q3 = 2.91 nC.)
N · m2/C
anonymous
 4 years ago
Find the net electric flux through the spherical closed surface shown in the figure below. The two charges on the right are inside the spherical surface. (Take q1 = +1.84 nC, q2 = +1.02 nC, and q3 = 2.91 nC.) N · m2/C

This Question is Closed

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0By Gauss' theorem, the flux through a Gaussian surface is equal to the sum of the charges inside the surface scaled by 1/4.pi.e0. use that result.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0they're the only charges in the surface, yes. I strongly recommend you watch the lecture I just linked in your other question.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0**correction: no 4.pi. That goes away in the integration.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i was wondering why i was getting the wrong answer lol

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0You know you're in danger in Physics when you're using equations and you don't know where they come from. Use that rule to be intellectually honest with yourself: what is this equation, where did come from, what does it mean physically, can I derive it from first principles in physics?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm... so I'm getting ((1.02x10^9)(2.91x10^9)/8.85x10^12=2.14x10^20 ?? that doesn't seem right

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0That's not the value of the permittivity in a vacuum. http://en.wikipedia.org/wiki/Vacuum_permittivity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops.. i had put 12 in the calculator.. but not on here. my bad.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Also the charges are in nano Coulomb, not giga Coulomb ! 9, not +9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0god.. i hate stupid mistakes. lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.