This question is for trigonometry. I will type the question first and then draw the picture that goes with the problem. A two person tent is to be made so that the height at the center is a=5 feet. If the sides of the tent are to meet the ground at an angle @=30 degrees, and the tent is to be b=9 feet in length, how many square feet of material will be needed to make the tent?

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This question is for trigonometry. I will type the question first and then draw the picture that goes with the problem. A two person tent is to be made so that the height at the center is a=5 feet. If the sides of the tent are to meet the ground at an angle @=30 degrees, and the tent is to be b=9 feet in length, how many square feet of material will be needed to make the tent?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1327537750183:dw| So the problem is like this?
|dw:1327537850715:dw|
ok that makes more sense

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|dw:1327538013379:dw|
find the hypotenuse of the end using Sin30 = 5/h or h = 5/sin(30) h should be equal to 10ft... 2 rectangles 10 x 9 will give the answer so lond as the tent does't have a floor
My apologies. I forgot one part that is with the question. Assume that the tent has a floor and is closed at both ends and give your answer in exact form.
first lets slove this sense you can see that it is a isolated triangle and it is cut in half. so it is a 90-60-30 triangle and the hieght is 9 which you can get that the shorter side is 3sqrt(3) and then the hypotenuse is 6sqrt(3)
then 6sqrt(3)*6=36sqrt(3)*2(cuz there are two big rectangles)
The center equals 5 (where the right angle is at). The rectangle length equals 9. Sorry. The "a" and "9" look the same in the drawing.
look at the triangular end..... |dw:1327538126180:dw| tan30 = 5/x x =5/tan30 \[5/\tan(30) = 5\sqrt{5}\] double it to get the width of the tent.... \[10\sqrt{?}\] Areas: Triangular ends (1/2 x 5 x 10sqrt(5) ) x 2 Floor (10sqrt(5) x 9) sloping sides....see above
Would x= 5\[\sqrt{3}\] and the hypotenuse would equal 10?
x equal 5 Squareroot 3
thats right... my typo
For the rectangles, I would do 2(10)+2(9)=38. Since there are three rectangles (sides and floor), I multiply 38 x 3=114. For the triangles, how do I addd together the numbers I figured out for the hypotenuse and the sides? Do I add the 5 square root 3 together, add the two hypotenuse together and then multiple each answer by two since there's two triangle areas (front and back of tent).?

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