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anonymous
 5 years ago
This question is for trigonometry. I will type the question first and then draw the picture that goes with the problem.
A two person tent is to be made so that the height at the center is a=5 feet. If the sides of the tent are to meet the ground at an angle @=30 degrees, and the tent is to be b=9 feet in length, how many square feet of material will be needed to make the tent?
anonymous
 5 years ago
This question is for trigonometry. I will type the question first and then draw the picture that goes with the problem. A two person tent is to be made so that the height at the center is a=5 feet. If the sides of the tent are to meet the ground at an angle @=30 degrees, and the tent is to be b=9 feet in length, how many square feet of material will be needed to make the tent?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327537750183:dw So the problem is like this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327537850715:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok that makes more sense

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1327538013379:dw

campbell_st
 5 years ago
Best ResponseYou've already chosen the best response.0find the hypotenuse of the end using Sin30 = 5/h or h = 5/sin(30) h should be equal to 10ft... 2 rectangles 10 x 9 will give the answer so lond as the tent does't have a floor

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My apologies. I forgot one part that is with the question. Assume that the tent has a floor and is closed at both ends and give your answer in exact form.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first lets slove this sense you can see that it is a isolated triangle and it is cut in half. so it is a 906030 triangle and the hieght is 9 which you can get that the shorter side is 3sqrt(3) and then the hypotenuse is 6sqrt(3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then 6sqrt(3)*6=36sqrt(3)*2(cuz there are two big rectangles)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The center equals 5 (where the right angle is at). The rectangle length equals 9. Sorry. The "a" and "9" look the same in the drawing.

campbell_st
 5 years ago
Best ResponseYou've already chosen the best response.0look at the triangular end..... dw:1327538126180:dw tan30 = 5/x x =5/tan30 \[5/\tan(30) = 5\sqrt{5}\] double it to get the width of the tent.... \[10\sqrt{?}\] Areas: Triangular ends (1/2 x 5 x 10sqrt(5) ) x 2 Floor (10sqrt(5) x 9) sloping sides....see above

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Would x= 5\[\sqrt{3}\] and the hypotenuse would equal 10?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x equal 5 Squareroot 3

campbell_st
 5 years ago
Best ResponseYou've already chosen the best response.0thats right... my typo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the rectangles, I would do 2(10)+2(9)=38. Since there are three rectangles (sides and floor), I multiply 38 x 3=114. For the triangles, how do I addd together the numbers I figured out for the hypotenuse and the sides? Do I add the 5 square root 3 together, add the two hypotenuse together and then multiple each answer by two since there's two triangle areas (front and back of tent).?
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