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anonymous
 4 years ago
Let F(s)=5s^2+5s+4. Find a value of d greater than 0 such that the average rate of change of F(s) from 0 to d equals instantaneous rate of change of F(s) at s=1.
anonymous
 4 years ago
Let F(s)=5s^2+5s+4. Find a value of d greater than 0 such that the average rate of change of F(s) from 0 to d equals instantaneous rate of change of F(s) at s=1.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is a similar prob to what i posted earlier but im getting the wrong answer so im doing something wrong

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1The average rate of change of F(s) from 0 to d is the average of F'(s) from 0 to d, which is \[ \frac{1}{d} \int_0^d dF/ds \ ds = \frac{F(d)  F(0)}{d} \] Hence you want to find a d such that \[ \frac{F(d)  F(0)}{d} = F'(1) \] So now you just need to evaluate.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hold on. im processing this information. lol

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.15d + 5 I agree with. Calculate F'(1) again.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk what im doing wrong

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1No, you want the value of dF/ds when s = 1. That's what F'(1) means.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1F'(s) = 10s + 5. Hence F'(1) = ...?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i wasnt plugging in i was setting equal to 1
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