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anonymous

  • 4 years ago

Please help...I don't know what to do or even where to start. Given the equation (x+3)^2+y^2=16 (a) find the center and the radius (b) graph (c) find the intercepts, if any.

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  1. anonymous
    • 4 years ago
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    foil first

  2. anonymous
    • 4 years ago
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    (x+3)(x+3)

  3. anonymous
    • 4 years ago
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    x=-3 and y=0 center radius =4

  4. asnaseer
    • 4 years ago
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    the general equation of a circle is:\[(x-a)^2+(y-b)^2=r^2\]where (a,b) is the coordinate of the center of the circle, and r is its radius.

  5. anonymous
    • 4 years ago
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    |dw:1327549404656:dw|

  6. anonymous
    • 4 years ago
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    x when x=0 y= +-4

  7. asnaseer
    • 4 years ago
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    so if you rewrite your equation:\[(x+3)^2+y^2=16\]in the form you get:\[(x-(-3))^2+(y-0)^2=4^2\]from which you can see the center must be at (-3, 0) and the radius must be 4 as @cinar said above.

  8. anonymous
    • 4 years ago
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    I am sorry I made a mistake when x=0 y=+-sqrt7

  9. anonymous
    • 4 years ago
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    |dw:1327549640807:dw|

  10. asnaseer
    • 4 years ago
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    then, to find the intercepts you would do this: 1) x-intercept is when y=0, therefore:\[(x+3)^2+0^2=16\]\[x+3=\sqrt{16}=\pm4\]\[x=1 \text{ or } -7\] 2) y-intercept is when x=0, therefore:\[(0+3)^2+y^2=16\]\[9+y^2=16\]\[y^2=7\]\[y=\pm\sqrt{7}\]

  11. anonymous
    • 4 years ago
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    this one is better than I drew http://www.wolframalpha.com/input/?i=plot+%28x%2B3%29^2%2By^2%3D16

  12. anonymous
    • 4 years ago
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    so if i have to go in and graph and i have to type in the #s into a box that looks like this 1 what do i type where Grid axis from to xaxis yaxis Interval xaxis y axis

  13. anonymous
    • 4 years ago
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    or what is the difference between the axis and the interval

  14. anonymous
    • 4 years ago
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    x axis is 1 and -7 interval is -7<=x<=1 y axis is sqrt7 and -sqrt7 but interval is -4<=y<=4 I dont know what grid is

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