anonymous
  • anonymous
2/3 of the men are married to 3/4 of the women in Fractionville. What fraction of the people in Fractionville are married? I've gotten it to 2/3x = 3/4y but I'm not sure what to do from here.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
you should have two equations, since you have two unknowns. so if you let x+y=1 you should be in good shape. (x and y are the corresponding fractions of the town that are male and female)
phi
  • phi
you need another equation x+y=1 means the men and women add up to the total population
anonymous
  • anonymous
x = the number of men in fractionville and y = the number of women in fractionville

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anonymous
  • anonymous
how can x + y = 1 though?
anonymous
  • anonymous
if x is the fraction of the population that is male and y is the fraction of the town that is female, they should add up to 1 which is the fraction of people in the population
anonymous
  • anonymous
but how is x the fraction of- okay I kinda see, but explain how i get my x and y definitions?
asnaseer
  • asnaseer
@JunkieJim is correct
anonymous
  • anonymous
i just dont understand it though shouldnt x + y = P (population)?
anonymous
  • anonymous
Yes, that's exactly what we're doing, only we're dividing everything by P so you've got \[\frac{x}{Population} +\frac{y}{Population} = \frac{Population}{Population}\] so that everything remains as fractions
phi
  • phi
Think of it this way: some fraction of the people are men and some fraction are women so x+y=1 the fraction of the population that are married is 2/3 x (another fraction)
phi
  • phi
which of course is the same fraction as 3/4 y
anonymous
  • anonymous
I appreciate how you are taking the time to explain it to me. And I'm understanding it better. I can do the systems from here, but that x + y = 1 is bothering me
anonymous
  • anonymous
what you said makes sense Phi, I'm just wondering how i got my definitions for x and y
asnaseer
  • asnaseer
@mridrik: another way of looking at this is to call the total population p and the number of men m. then, number of women = p - m and you can write:\[\frac{2m}{3}=\frac{3(p-m)}{4}\]
phi
  • phi
your definitions should be modified x = the fraction of the population that are men in fractionville and y = the fraction of the population that are women in fractionville
anonymous
  • anonymous
so are my definitions wrong, or are they right but do not help me advance with the problem?
phi
  • phi
I would *not* use x = the number of men in fractionville and y = the number of women in fractionville
anonymous
  • anonymous
with asnaseers way, we get m = 9/17p, so how could I use that to get the answer?
asnaseer
  • asnaseer
2m/3 are married
phi
  • phi
you can only find m/p (a fraction)
anonymous
  • anonymous
so 2/3 * 9/17 gives us ?
anonymous
  • anonymous
now I'm confused again
phi
  • phi
the fraction married
anonymous
  • anonymous
but we already knew the fraction married 2/3
anonymous
  • anonymous
i have a feeling i sound pretty stupid right now to you guys
asnaseer
  • asnaseer
no - 2/3 is the fraction of men that are married - not the fraction of the population that are married.
phi
  • phi
double it (we have to count the women)
anonymous
  • anonymous
so 2/3 * 9/17 * 2?
phi
  • phi
Sounds good. we know 2/3 * 9/17 = 6/17 of the population is married men 3/4 * 8/17 is 6/17 of the population = married women total fraction 12/17
anonymous
  • anonymous
You guys are genii! (I think thats genius plural) Thank you, so 12/17 of the population of fractionville is married?
asnaseer
  • asnaseer
:) we've just had a bit more practice than you have mridrik thats all. and yes phi has the correct answer.
anonymous
  • anonymous
It makes me happy to know that people care about another's will to learn.
asnaseer
  • asnaseer
thats what makes this site so wonderful :)
anonymous
  • anonymous
If i could, i would make a program that gave each of you over 9000 medals
asnaseer
  • asnaseer
:O) - careful - we may drown in glory - lol!
anonymous
  • anonymous
yeah lol, my math teacher couldnt even get this today in class
asnaseer
  • asnaseer
try and be gentle on him - after all - he is also human :)
anonymous
  • anonymous
yes, maybe I'll get the chance to explain what you showed me to the class, even though i dont that well with public speaking, only about 20 students in my algebra 2 class
asnaseer
  • asnaseer
good luck my friend...
anonymous
  • anonymous
thanks for your help, have you ever heard of mathcounts?
asnaseer
  • asnaseer
no - what are they?
anonymous
  • anonymous
It's a program that my school participtes in with schools from around the United States, we go to regionals first, (district is too small) and usually win that, and then go to state where this one girl always wins, its from 6th to 8th grade (my last year) and its a blast when we go there to lexington this year (KY) but they questions get ridiculously hard towards the end of the competition and i bet you would beast them up
asnaseer
  • asnaseer
I'm sure as time goes by you will become a mathematical ninja and win that contest hands down :) I'm probably far too old for that now :)
anonymous
  • anonymous
oh no way, the way you win is the top ten scorers in the written test get to go to a quick recall type thing, and she has won that in 6th grade and 7th grade, I got 40 something place and my friend got in the 30s, but there are a LOT of people there so thats pretty good i guess, our school got 10th place overall last year
asnaseer
  • asnaseer
that is an extremely good achievement. and never think that you will not be able to achieve even better goals for yourself - nothing in this world is impossible if you work hard enough at it. you certainly sound like someone who is willing to work hard to achieve high goals in life.
anonymous
  • anonymous
Thanks, I would like to be an engineer when I grow up, not really sure what they do, but everyone says it involves math so that sounds fun.
asnaseer
  • asnaseer
yes - there is a lot of maths involved in engineering. your main focus should be to do something you really enjoy - after all, you will most likely be working for the rest of your life in one particular job - so might as well pick something you really enjoy. anyway - must go now. good talking to you.
anonymous
  • anonymous
you too

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