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anonymous
 4 years ago
2/3 of the men are married to 3/4 of the women in Fractionville. What fraction of the people in Fractionville are married?
I've gotten it to 2/3x = 3/4y but I'm not sure what to do from here.
anonymous
 4 years ago
2/3 of the men are married to 3/4 of the women in Fractionville. What fraction of the people in Fractionville are married? I've gotten it to 2/3x = 3/4y but I'm not sure what to do from here.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you should have two equations, since you have two unknowns. so if you let x+y=1 you should be in good shape. (x and y are the corresponding fractions of the town that are male and female)

phi
 4 years ago
Best ResponseYou've already chosen the best response.2you need another equation x+y=1 means the men and women add up to the total population

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x = the number of men in fractionville and y = the number of women in fractionville

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how can x + y = 1 though?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if x is the fraction of the population that is male and y is the fraction of the town that is female, they should add up to 1 which is the fraction of people in the population

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but how is x the fraction of okay I kinda see, but explain how i get my x and y definitions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just dont understand it though shouldnt x + y = P (population)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, that's exactly what we're doing, only we're dividing everything by P so you've got \[\frac{x}{Population} +\frac{y}{Population} = \frac{Population}{Population}\] so that everything remains as fractions

phi
 4 years ago
Best ResponseYou've already chosen the best response.2Think of it this way: some fraction of the people are men and some fraction are women so x+y=1 the fraction of the population that are married is 2/3 x (another fraction)

phi
 4 years ago
Best ResponseYou've already chosen the best response.2which of course is the same fraction as 3/4 y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I appreciate how you are taking the time to explain it to me. And I'm understanding it better. I can do the systems from here, but that x + y = 1 is bothering me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what you said makes sense Phi, I'm just wondering how i got my definitions for x and y

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2@mridrik: another way of looking at this is to call the total population p and the number of men m. then, number of women = p  m and you can write:\[\frac{2m}{3}=\frac{3(pm)}{4}\]

phi
 4 years ago
Best ResponseYou've already chosen the best response.2your definitions should be modified x = the fraction of the population that are men in fractionville and y = the fraction of the population that are women in fractionville

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so are my definitions wrong, or are they right but do not help me advance with the problem?

phi
 4 years ago
Best ResponseYou've already chosen the best response.2I would *not* use x = the number of men in fractionville and y = the number of women in fractionville

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0with asnaseers way, we get m = 9/17p, so how could I use that to get the answer?

phi
 4 years ago
Best ResponseYou've already chosen the best response.2you can only find m/p (a fraction)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 2/3 * 9/17 gives us ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now I'm confused again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but we already knew the fraction married 2/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have a feeling i sound pretty stupid right now to you guys

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2no  2/3 is the fraction of men that are married  not the fraction of the population that are married.

phi
 4 years ago
Best ResponseYou've already chosen the best response.2double it (we have to count the women)

phi
 4 years ago
Best ResponseYou've already chosen the best response.2Sounds good. we know 2/3 * 9/17 = 6/17 of the population is married men 3/4 * 8/17 is 6/17 of the population = married women total fraction 12/17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You guys are genii! (I think thats genius plural) Thank you, so 12/17 of the population of fractionville is married?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2:) we've just had a bit more practice than you have mridrik thats all. and yes phi has the correct answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It makes me happy to know that people care about another's will to learn.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2thats what makes this site so wonderful :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If i could, i would make a program that gave each of you over 9000 medals

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2:O)  careful  we may drown in glory  lol!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah lol, my math teacher couldnt even get this today in class

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2try and be gentle on him  after all  he is also human :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, maybe I'll get the chance to explain what you showed me to the class, even though i dont that well with public speaking, only about 20 students in my algebra 2 class

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2good luck my friend...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for your help, have you ever heard of mathcounts?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's a program that my school participtes in with schools from around the United States, we go to regionals first, (district is too small) and usually win that, and then go to state where this one girl always wins, its from 6th to 8th grade (my last year) and its a blast when we go there to lexington this year (KY) but they questions get ridiculously hard towards the end of the competition and i bet you would beast them up

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2I'm sure as time goes by you will become a mathematical ninja and win that contest hands down :) I'm probably far too old for that now :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh no way, the way you win is the top ten scorers in the written test get to go to a quick recall type thing, and she has won that in 6th grade and 7th grade, I got 40 something place and my friend got in the 30s, but there are a LOT of people there so thats pretty good i guess, our school got 10th place overall last year

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2that is an extremely good achievement. and never think that you will not be able to achieve even better goals for yourself  nothing in this world is impossible if you work hard enough at it. you certainly sound like someone who is willing to work hard to achieve high goals in life.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks, I would like to be an engineer when I grow up, not really sure what they do, but everyone says it involves math so that sounds fun.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.2yes  there is a lot of maths involved in engineering. your main focus should be to do something you really enjoy  after all, you will most likely be working for the rest of your life in one particular job  so might as well pick something you really enjoy. anyway  must go now. good talking to you.
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