anonymous
  • anonymous
How to put y=4cos(x) in X= form?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[x=\cos^{-1} (y/4)\]
anonymous
  • anonymous
It is only allowed in said domain in order to make it the inverse function (It needs to pass the horizontal line test)
anonymous
  • anonymous
Inverse y = 4cos(x) x/4 = 4cos(x)/4 y/4 = cos(x) take inverse of each side arccos(y/4) = arccos(cos(x)) arccos(y/4) = 1x arccos(y/4) = x Remember that arccos is the inverse function of cos(x) and is limited to the domain [0, pi]

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anonymous
  • anonymous
ignore the mistake i made in the variables
anonymous
  • anonymous
Here is the problem I'm working at:
anonymous
  • anonymous
Find the volume of the solid generated by revolving the described region about the given axis: The region in the first quadrant bounded above by the line y=4 and by the curve y=4sin(x) for the interval 0≤x≤π2 about the line y=4
anonymous
  • anonymous
I think I'm using the cross-section method, but am not too sure on the radius.
anonymous
  • anonymous
Which I think would be (4-4sin(x)
anonymous
  • anonymous
Wait do you want 4sin(x) to equal 4?
anonymous
  • anonymous
I'm honestly not too sure on where to start with this problem.
anonymous
  • anonymous
I'm confused by your question but if you want it to equal four you can use the unit circle and think where is cos(x) = 1, the answer being pi
anonymous
  • anonymous
Are you familiar with solids of rotation?
anonymous
  • anonymous
tbh no I know trig functions though but meh you should ask in chat for help
anonymous
  • anonymous
haha alright, thanks for the help
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=plot+y%3D4sin%28x%29
anonymous
  • anonymous
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anonymous
  • anonymous
@Cinar, do you know which method I would use here?
anonymous
  • anonymous
little bit (: I am trying to find it
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anonymous
  • anonymous
Sweet, thanks
anonymous
  • anonymous
what is the rotation axis?
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anonymous
  • anonymous
it is y=4
anonymous
  • anonymous
so I'm thinking the radius is (4-4sin(x))
anonymous
  • anonymous
Any luck?
anonymous
  • anonymous
nope
anonymous
  • anonymous
\[V=\pi \int\limits_{0}^{2\pi}(4-4\sin x)^2dx\]
anonymous
  • anonymous
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