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How to put y=4cos(x) in X= form?

Mathematics
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\[x=\cos^{-1} (y/4)\]
It is only allowed in said domain in order to make it the inverse function (It needs to pass the horizontal line test)
Inverse y = 4cos(x) x/4 = 4cos(x)/4 y/4 = cos(x) take inverse of each side arccos(y/4) = arccos(cos(x)) arccos(y/4) = 1x arccos(y/4) = x Remember that arccos is the inverse function of cos(x) and is limited to the domain [0, pi]

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Other answers:

ignore the mistake i made in the variables
Here is the problem I'm working at:
Find the volume of the solid generated by revolving the described region about the given axis: The region in the first quadrant bounded above by the line y=4 and by the curve y=4sin(x) for the interval 0≤x≤π2 about the line y=4
I think I'm using the cross-section method, but am not too sure on the radius.
Which I think would be (4-4sin(x)
Wait do you want 4sin(x) to equal 4?
I'm honestly not too sure on where to start with this problem.
I'm confused by your question but if you want it to equal four you can use the unit circle and think where is cos(x) = 1, the answer being pi
Are you familiar with solids of rotation?
tbh no I know trig functions though but meh you should ask in chat for help
haha alright, thanks for the help
http://www.wolframalpha.com/input/?i=plot+y%3D4sin%28x%29
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@Cinar, do you know which method I would use here?
little bit (: I am trying to find it
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Sweet, thanks
what is the rotation axis?
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it is y=4
so I'm thinking the radius is (4-4sin(x))
Any luck?
nope
\[V=\pi \int\limits_{0}^{2\pi}(4-4\sin x)^2dx\]
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