Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Can someone explain to me the difference and application of the two formulas lim (f(x+h) - f(x))/h h->0 lim (f(x) - f(a))/(x-a) x->a Also what does this relate to: y = f'(a) (x-a) + f(a)

Calculus1
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

To make it clear I understand that the first equation is the definition of the derivative, where does the second formula come from?
they are identical, they just look different. take the second one, replace \[x-a\] by \[h\] and you will see that there is no difference
\[h\] and \[x-a\] are both different ways of expressing the change in x for the secant line of a function. The first equation shows the limit of the function as the change of x tends directly to zero. The second function shows the limit of the function as x tends to a; as x gets really close to a, the change in x also approaches zero. They are the same function, one just uses a new variable (h) to describe the change in x.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question