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anonymous

  • 5 years ago

how would i solve this.... 1-3y/5 =2

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  1. asnaseer
    • 5 years ago
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    is this:\[\text{a) }1-\frac{3y}{5}=2\]or,\[\text{b) }\frac{1-3y}{5}=2\]

  2. anonymous
    • 5 years ago
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    b

  3. asnaseer
    • 5 years ago
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    ok, first step would be to multiply both sides by 5 to get rid of the denominator on the left hand side

  4. anonymous
    • 5 years ago
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    ok

  5. anonymous
    • 5 years ago
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    is the answer y =- 1/3

  6. asnaseer
    • 5 years ago
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    so you woud get:\[5*\frac{1-3y}{5}=5*2\]\[\cancel{5}*\frac{1-3y}{\cancel{5}}=5*2\]\[1-3y=10\]

  7. anonymous
    • 5 years ago
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    oh okay i found out what i did wrong i multiply 5 with the other numbers on top too.. thank you

  8. asnaseer
    • 5 years ago
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    yw

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