## anonymous 4 years ago how would i solve this.... 1-3y/5 =2

1. asnaseer

is this:$\text{a) }1-\frac{3y}{5}=2$or,$\text{b) }\frac{1-3y}{5}=2$

2. anonymous

b

3. asnaseer

ok, first step would be to multiply both sides by 5 to get rid of the denominator on the left hand side

4. anonymous

ok

5. anonymous

is the answer y =- 1/3

6. asnaseer

so you woud get:$5*\frac{1-3y}{5}=5*2$$\cancel{5}*\frac{1-3y}{\cancel{5}}=5*2$$1-3y=10$

7. anonymous

oh okay i found out what i did wrong i multiply 5 with the other numbers on top too.. thank you

8. asnaseer

yw