how would i solve this.... 1-3y/5 =2

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how would i solve this.... 1-3y/5 =2

Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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is this:\[\text{a) }1-\frac{3y}{5}=2\]or,\[\text{b) }\frac{1-3y}{5}=2\]
b
ok, first step would be to multiply both sides by 5 to get rid of the denominator on the left hand side

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ok
is the answer y =- 1/3
so you woud get:\[5*\frac{1-3y}{5}=5*2\]\[\cancel{5}*\frac{1-3y}{\cancel{5}}=5*2\]\[1-3y=10\]
oh okay i found out what i did wrong i multiply 5 with the other numbers on top too.. thank you
yw

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