A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Let f(x)=x^2+x+13. What is the value of x for which the tangent line to the graph of y=f(x) is parallel to the xaxis?
anonymous
 4 years ago
Let f(x)=x^2+x+13. What is the value of x for which the tangent line to the graph of y=f(x) is parallel to the xaxis?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have no idea how to do this

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.2\[f(x)=x^2+x+13\]\[f'(x)=2x+1\] Any line is parallel to the xaxis when its slope is 0, so find x for when the tangent line's slope is equal to 0: 0 = 2x+1 1=2x x = 1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@above? how is the line vertical and tangent to that graph at the same time?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see, maybe, sorry

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.2The line is horizontal, because the xaxis is horizontal. Two horizontal lines are parallel.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i didnt see that it said xvalue, i put the actual line that was tangent and parallel

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i messed that part up too!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the equation for the tangent line would be y = 51/4

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.2The equation for the tangent line would be: \[y=\frac{1}{2}x+13\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, plug the axis of symmetry (1/2) in for x to get 12 3/4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and yours isnt even horizontal

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.2I apologize. The equation for the tangent line would be: \[y=13\] \[(\frac{1}{2},\frac{51}{4}) \]is actually the vertex point for the original equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y = 13? That would touch it at two points though. You got the vertex, now you just need a horizontal line with the ycoordinate of the vertex so that it touches the vertex.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.