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anonymous

  • 4 years ago

given the equation y=-2x^2+4, calculate the corresponding y-cordinates for x=-3, -1, 0, 1, 3 show all work

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  1. anonymous
    • 4 years ago
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    @ x=-3 ,\[y= -2(-3)^{2}+4 = -14\] @ x= -1 , \[y= -2(-1)^{2}+4 = 2\] @ x= 0 , \[y= -2(0)^{2}+4 = 4\] @ x= 1 , \[y= -2(1)^{2}+4 = 2\] @ x= 3 , \[y= -2(3)^{2}+4 = -14\]

  2. anonymous
    • 4 years ago
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    So when it comes to graphin this how do I know what is what. I have to enter it into an ez graph application. Which is x,y intercepts and then what is the x, y intervals

  3. anonymous
    • 4 years ago
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    i dont know what is the ez graph application .. but the y-intercept is the part of the y-axis that the function cuts , in which the abcissa of the point is 0 and the ordinate has a definite value , which means that when you substitute by x =0 in the function you get the y-intercept ,, and the x- intercept is the of the x-axis that the function cuts ,,,,,, and about the interval it means all possible values of X, that belongs to the domain , which have corresponding values in Y|dw:1327541395869:dw|

  4. anonymous
    • 4 years ago
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    -3,3 is the domain ,,,,, f(-3),f(3) is the monotony

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