## electrochika 4 years ago At time t equals or > 0, the acceleration of a particle moving on the x axis is a(t)=t+sint.?

1. electrochika

at t=0 the velocity of the particle is -2. for what value t will the velocity of the particle be zero?

2. anonymous

To find a velocity equation from an acceleration equation, you need to differentiate the acceleration equation with respect to t: $a'(t)=\cos(t)$Now find the values for which this equation is equal to 0. $0=\cos(t)$$t=\pi/2, 3\pi/2$

3. TuringTest

$v(t)=\int a(t)dt=\frac1 2t^2-\cos t+C$$v(0)=-1-2=C=-3$$v(t)=\frac1 2t^2-\cos t-3=0$solve for t

4. anonymous

think this might be backwards you are given acceleration and you want velocity

5. TuringTest

Xishem has it backwards, yes

6. anonymous

what turing test said.

7. anonymous

Yep.

8. electrochika

So t = - 2.917 and 2.917?

9. TuringTest

yes, and I would imagine we want the positive answer here

10. electrochika

yeah we do

11. TuringTest

oh yeah, positive only it says so in the problem