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electrochika

  • 4 years ago

At time t equals or > 0, the acceleration of a particle moving on the x axis is a(t)=t+sint.?

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  1. electrochika
    • 4 years ago
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    at t=0 the velocity of the particle is -2. for what value t will the velocity of the particle be zero?

  2. Xishem
    • 4 years ago
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    To find a velocity equation from an acceleration equation, you need to differentiate the acceleration equation with respect to t: \[a'(t)=\cos(t)\]Now find the values for which this equation is equal to 0. \[0=\cos(t)\]\[t=\pi/2, 3\pi/2\]

  3. TuringTest
    • 4 years ago
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    \[v(t)=\int a(t)dt=\frac1 2t^2-\cos t+C\]\[v(0)=-1-2=C=-3\]\[v(t)=\frac1 2t^2-\cos t-3=0\]solve for t

  4. anonymous
    • 4 years ago
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    think this might be backwards you are given acceleration and you want velocity

  5. TuringTest
    • 4 years ago
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    Xishem has it backwards, yes

  6. anonymous
    • 4 years ago
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    what turing test said.

  7. Xishem
    • 4 years ago
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    Yep.

  8. electrochika
    • 4 years ago
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    So t = - 2.917 and 2.917?

  9. TuringTest
    • 4 years ago
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    yes, and I would imagine we want the positive answer here

  10. electrochika
    • 4 years ago
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    yeah we do

  11. TuringTest
    • 4 years ago
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    oh yeah, positive only it says so in the problem

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