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smurfy14

  • 4 years ago

y=cos(-0.4x) has a horizontal stretch of..? PLEASE HELP

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  1. anonymous
    • 4 years ago
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    you mean period?

  2. smurfy14
    • 4 years ago
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    oh yes

  3. anonymous
    • 4 years ago
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    are you looking for the period of \[\cos(-.4x)\]?

  4. smurfy14
    • 4 years ago
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    yes

  5. smurfy14
    • 4 years ago
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    im looking for something like "it stretches X..."

  6. anonymous
    • 4 years ago
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    period of \[\cos(x)\] is \[2\pi\] so period of \[\cos(bx)\] is \[\frac{2\pi}{b}\]

  7. anonymous
    • 4 years ago
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    in your case you get \[\frac{2\pi}{.4}=5\pi\]

  8. smurfy14
    • 4 years ago
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    no heres an example: y=-3cos1/2x has a horizontal stretch of 2 but i cant figure out what it would be for this problem

  9. anonymous
    • 4 years ago
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    so period goes from 2 pi to 5 pi

  10. anonymous
    • 4 years ago
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    oooooooooooooooh silly way to word the problem. in your case \[\cos(\frac{1}{2}x)\] teh "stretch" was 2

  11. anonymous
    • 4 years ago
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    in other words the reciprocal of coefficient. the reciprocal of .4 is 5, so stretch is 5

  12. smurfy14
    • 4 years ago
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    ohhhkay so you dont have to include the whole thing like 2/5=5/2 you just take the numerator?

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