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anonymous

  • 4 years ago

what is the surface area of a cylinder that is r=9cm,h=15cm round to tenth of a square unit

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  1. anonymous
    • 4 years ago
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    Well, let us start with what counts as surface area. Can you explain?

  2. anonymous
    • 4 years ago
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    no i cant the book just give me r=9cm,h=15cm

  3. anonymous
    • 4 years ago
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    Forget dimensions. Start with cylinder shape. What would be part of its "surface"?

  4. anonymous
    • 4 years ago
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    is it 2(pir2)+(2pir)

  5. anonymous
    • 4 years ago
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    Well....you are missing the length of the cylinder.

  6. anonymous
    • 4 years ago
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    If you get the concept of the surface of a cylinder as the are of two circles on top and bottom, plus the length of the circumference of the circle across the cylinder, then you will be right. Then, it is a matter of figuring out the "formulas" and plugging values of the respective dimensions.

  7. anonymous
    • 4 years ago
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    i got 254.469 as my answer

  8. anonymous
    • 4 years ago
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    i think i did something wrong

  9. anonymous
    • 4 years ago
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    2*pi*9^2 + 2*pi*9*15

  10. Mertsj
    • 4 years ago
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    The area of the top which is a circle is pir^2 So the top and bottom area is the total of the two circles or 2pir^2. The radius is 9 so that makes a total of 162pi. Now how about the rest of the cylinder. We have eliminated the top and bottom of the "can" so not we have a tube left. If we split the "tube" open, we will have a rectangle. The height of the rectangle is the height of the cylinder and the base of the rectangle is the circumference of the circle. so the area of the rectangle is 2pir(h) Add that to the 162pi and you will have the total area or 432 pi

  11. anonymous
    • 4 years ago
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    thank you now im able to complete my others problems like this

  12. anonymous
    • 4 years ago
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    AWESOME!!! YOU ARE GREAT!

  13. anonymous
    • 4 years ago
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    thanks you

  14. Mertsj
    • 4 years ago
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    |dw:1327543409182:dw|

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