anonymous
  • anonymous
Find a vector U that is tangent to the graph of y=x^2-x+3 at the point (2,5)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
slope is 5 vector is |dw:1327542825433:dw|
anonymous
  • anonymous
The answer is actually <1, 3> and I am asking for an explanation why
anonymous
  • anonymous
oh...sry, that's right

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anonymous
  • anonymous
Using derivatives, if you get the first derivative of the quadratic above, we get slope=2x-1 when we plug 2 in, we get slope=3 put this in vector form, we get (1,3)
anonymous
  • anonymous
added 1 by mistake on the first try :(
anonymous
  • anonymous
ah, that simple. Thanks!
anonymous
  • anonymous
welcome!

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