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anonymous

  • 4 years ago

Find a vector U that is tangent to the graph of y=x^2-x+3 at the point (2,5)

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  1. anonymous
    • 4 years ago
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    slope is 5 vector is |dw:1327542825433:dw|

  2. anonymous
    • 4 years ago
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    The answer is actually <1, 3> and I am asking for an explanation why

  3. anonymous
    • 4 years ago
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    oh...sry, that's right

  4. anonymous
    • 4 years ago
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    Using derivatives, if you get the first derivative of the quadratic above, we get slope=2x-1 when we plug 2 in, we get slope=3 put this in vector form, we get (1,3)

  5. anonymous
    • 4 years ago
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    added 1 by mistake on the first try :(

  6. anonymous
    • 4 years ago
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    ah, that simple. Thanks!

  7. anonymous
    • 4 years ago
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    welcome!

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spraguer (Moderator)
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