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anonymous

  • 4 years ago

Can anyone explain the reduction method used to calculate the determinant of a large square matrix?

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  1. anonymous
    • 4 years ago
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    It is credited to lewis carroll

  2. TuringTest
    • 4 years ago
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    I did not know that^ interesting... basically all it is is using elimination to get the matrix to be upper-triangular, which makes the derivative easier to compute here are some good notes on the topic http://tutorial.math.lamar.edu/Classes/LinAlg/DeterminantByRowReduction.aspx

  3. TuringTest
    • 4 years ago
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    the determinant easier to compute*

  4. anonymous
    • 4 years ago
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    Thanks turing :D That is exactly what i needed

  5. TuringTest
    • 4 years ago
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    happy to help!

  6. anonymous
    • 4 years ago
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    http://www.maa.org/mathtourist/mathtourist_03_19_07.html

  7. anonymous
    • 4 years ago
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    I think this is the one I was referring to. It is actually quite interesting

  8. TuringTest
    • 4 years ago
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    Oh, this is a little different that the method I linked you to. Never seen this one before, but it seems cool.

  9. anonymous
    • 4 years ago
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    yup never ever seen it either. I dont think it is used now a days

  10. TuringTest
    • 4 years ago
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    The link you showed me is news to me do you want me to try to clear up anything about it in particular?

  11. anonymous
    • 4 years ago
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    ummm can u just say in short what he did?

  12. anonymous
    • 4 years ago
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    I have to write a lil paragraph abt it

  13. anonymous
    • 4 years ago
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    only if u want to:D You dont have to

  14. anonymous
    • 4 years ago
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    Turing I am not taking advantage over you:D All this while i am jotting down points

  15. TuringTest
    • 4 years ago
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    Well like I said this is new to me but it looks like we started with our 4x4 matrix A, which we duplicated all the middle rows and columns of. we then broke up the resulting 6x6 matrix into 3 2x2 matrices which we took the determinant of. this gives us a 3x3 matrix which we did the same to: duplicate all middle rows and columns, which gives a 4x4 matrix. The central term -7 is duplicated in all matrices, so that factor will need to be divided out in the end. after breaking up our 4x4 into 4 2x2 matrices (which we take the det of) we have a 2x2 which we take the det of. remembering to divide out the extra factor of -7 we picked up earlier gives us the final det. -Don't worry, this was interesting and new, thanks for showing me. I hope what I noticed about the problem helped, though since I am new to the method I'm not sure I can generalize it. Good luck!

  16. anonymous
    • 4 years ago
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    Thanks Turing

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