Let f(t)=8t^2+4t+1. Find the value of t for which the tangent line to the graph of f(t) has slope 1.

Let f(t)=8t^2+4t+1. Find the value of t for which the tangent line to the graph of f(t) has slope 1.

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\[f(t)=8t^2+4t+1\]\[f'(t)=16t+4\]\[1=16t+4\]\[t=\frac{-3}{16}\]

god i feel so slow. a lot of these are the same just phrased differently. thanks for all the help.

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