anonymous
  • anonymous
Factor this expression. Check by multiplying factors. x^2y+axy+abx+a^2b
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
factor demon to the rescue!
myininaya
  • myininaya
We should try factoring by grouping First two terms have xy in common so we can write \[xy(x+a)+abx+a^2b\] Last two terms have ab in common so we can write \[xy(x+a)+ab(x+a)\]
anonymous
  • anonymous
\[(x+a) (xy+ab)\]

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myininaya
  • myininaya
Yes that is the final answer :)
anonymous
  • anonymous
"factor by groupies"

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