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## anonymous 4 years ago Find the volume of the solid generated by revolving the described region about the given axis: The region bounded above by the line y=4 , below by the curve y=x^2 , rotated along the following lines: y=4

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1. anonymous

$\pi \int\limits_{-2}^{2}(x^2 - 4 ) ^2 dx$ If im not mistaken :) ( Im a bit rusty )

2. anonymous

Acutally π∫(4- x^2)2dx because y=4 > x^2 in the bounded area

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