• anonymous
Find the volume of the solid generated by revolving the region bounded by y=sqrt(x), y=0, and x=3 about the y-axis. My take on this was: x=y^2 on [0,9] since the information states that in terms of x, the interval is [0,3]. Therefore, by plugging in, (0)^2=0 and (3)^2=9. So: int (0,9) ((pi)(y^2)^2) dy =(pi)(1/5(x^5))|(0,9) Volume=(59049(pi)/5) cu. units. Correct?
  • Stacey Warren - Expert
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  • schrodinger
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  • anonymous
The main problem I have is that I feel as though I should be subtracting the volume of the area between y=0 and x=y^2 in order to get an accurate measurement. Am I right? How do I do this?

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