anonymous
  • anonymous
An artillery shell is fired at an angle of 62.7 above the horizontal ground with an initial speed of 1520 m/s. The acceleration of gravity is 9.8 m/s2 . Find the total time of flight of the shell, neglecting air resistance. Answer in units of min
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
vertical is 1520sin62.7 = 1350.69819 horizontal is 1520cos62.7 = 697.14732 s=ut +1/2 at^2 therefore 1350.698t +4.9t^2 t=277.77 seconds... and then divide 697.1432/277.77 = part b Can someone tell me if this is the correct answer, or if not what I am doing wrong.
anonymous
  • anonymous
isnt this a math question?
anonymous
  • anonymous
nope... university physics

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok did not see word gravity
anonymous
  • anonymous
no help ? :(
anonymous
  • anonymous
looking im trying to figure out
anonymous
  • anonymous
ok. thankyou
anonymous
  • anonymous
lol i can only see the first part of what you typed the rest i got lost
anonymous
  • anonymous
huh?
anonymous
  • anonymous
it got too crowded up
anonymous
  • anonymous
Assuming you plugged the values correctly into your calculator, that's correct. The procedure you went through is right. You need to convert from seconds to minutes, though. For part b, I assume you're looking for the total range of the projectile? In which case you need multiply the time of flight (in seconds) by the velocity.
anonymous
  • anonymous
hey eashmore
anonymous
  • anonymous
kyrstal. Didn't I answer this question for you already?
anonymous
  • anonymous
it is nt right :(
anonymous
  • anonymous
uhm
anonymous
  • anonymous
You need to watch your units. Your answer should be in minutes, not seconds, right?
anonymous
  • anonymous
im pulling it u one second.
anonymous
  • anonymous
up*
anonymous
  • anonymous
Well in your question it says minutes...
anonymous
  • anonymous
are you good with vectors?
anonymous
  • anonymous
it was right :/ just didnt read the whole problem.
anonymous
  • anonymous
The work you did was correct. As Jemurray3 correctly pointed out, you need to convert seconds to minutes.
anonymous
  • anonymous
can you help me with a math problem?

Looking for something else?

Not the answer you are looking for? Search for more explanations.