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anonymous
 4 years ago
An artillery shell is fired at an angle of 62.7
above the horizontal ground with an initial
speed of 1520 m/s.
The acceleration of gravity is 9.8 m/s2 .
Find the total time of flight of the shell,
neglecting air resistance.
Answer in units of min
anonymous
 4 years ago
An artillery shell is fired at an angle of 62.7 above the horizontal ground with an initial speed of 1520 m/s. The acceleration of gravity is 9.8 m/s2 . Find the total time of flight of the shell, neglecting air resistance. Answer in units of min

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0vertical is 1520sin62.7 = 1350.69819 horizontal is 1520cos62.7 = 697.14732 s=ut +1/2 at^2 therefore 1350.698t +4.9t^2 t=277.77 seconds... and then divide 697.1432/277.77 = part b Can someone tell me if this is the correct answer, or if not what I am doing wrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0isnt this a math question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nope... university physics

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok did not see word gravity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0looking im trying to figure out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i can only see the first part of what you typed the rest i got lost

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it got too crowded up

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Assuming you plugged the values correctly into your calculator, that's correct. The procedure you went through is right. You need to convert from seconds to minutes, though. For part b, I assume you're looking for the total range of the projectile? In which case you need multiply the time of flight (in seconds) by the velocity.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0kyrstal. Didn't I answer this question for you already?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You need to watch your units. Your answer should be in minutes, not seconds, right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im pulling it u one second.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well in your question it says minutes...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you good with vectors?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it was right :/ just didnt read the whole problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The work you did was correct. As Jemurray3 correctly pointed out, you need to convert seconds to minutes.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you help me with a math problem?
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