anonymous
  • anonymous
Factor this expression. Check by multiplying factors. 3ab+3ac+2b^2+2bc
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Mertsj
  • Mertsj
Are you learning how to do these? You keep posting the same type of problem.
anonymous
  • anonymous
Not at all.
Mertsj
  • Mertsj
Do you want to learn?

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More answers

anonymous
  • anonymous
I would love to.
Mertsj
  • Mertsj
Take the first two terms: 3ab +3ac What do they have in common?
anonymous
  • anonymous
Do you have Skype so we don't spam this feed?
Mertsj
  • Mertsj
No I don't
anonymous
  • anonymous
Ok well they share "a"
Mertsj
  • Mertsj
What else do they share?
anonymous
  • anonymous
3
Mertsj
  • Mertsj
Good. so factor out 3a and tell me what you get
anonymous
  • anonymous
1,3
Mertsj
  • Mertsj
|dw:1327549920542:dw|
Mertsj
  • Mertsj
Do you understand that?
anonymous
  • anonymous
Yes
Mertsj
  • Mertsj
Now take the last two terms which are 2b^+2bc What do they have in common?
anonymous
  • anonymous
2b
Mertsj
  • Mertsj
Factor it out
anonymous
  • anonymous
|dw:1327550017696:dw|
Mertsj
  • Mertsj
Factor out 2b. Not just 2
Mertsj
  • Mertsj
You said they have 2b in common and they do. So factor out 2b
anonymous
  • anonymous
|dw:1327550097535:dw|
Mertsj
  • Mertsj
|dw:1327550099915:dw|
Mertsj
  • Mertsj
I think that was my fault because I didn't get the exponent on the 2b^2
anonymous
  • anonymous
Hmm.
Mertsj
  • Mertsj
|dw:1327550268634:dw|
Mertsj
  • Mertsj
So you see that now we have 2 terms instead of 4?
anonymous
  • anonymous
Yes.
Mertsj
  • Mertsj
And what do those two terms have in common?
anonymous
  • anonymous
b
Mertsj
  • Mertsj
|dw:1327550319609:dw|
Mertsj
  • Mertsj
Do you see that they have (b+c) in common?
anonymous
  • anonymous
Yeah
Mertsj
  • Mertsj
Factor it out.
anonymous
  • anonymous
Factor out 9\b+c?)\
anonymous
  • anonymous
Wow, backspace is retartded
Mertsj
  • Mertsj
What did you say they have in common/
anonymous
  • anonymous
b+c
Mertsj
  • Mertsj
Then factor out b+c
anonymous
  • anonymous
They're alreadty factored out. Is your backspace working? Mine won't work on this website but others it will.
Mertsj
  • Mertsj
b+c times something equals the first term which is 3a(b+c)
Mertsj
  • Mertsj
Yes my backspace works.
Mertsj
  • Mertsj
Would you agree that (b+c)(3a )=3a(b+c)?
anonymous
  • anonymous
Yes.
Mertsj
  • Mertsj
Now consider the second term 2b(b+c) (b+c) times something = 2b(b+c) What is it?
anonymous
  • anonymous
2
Mertsj
  • Mertsj
2(b+c) does not equal 2b(b+c)
anonymous
  • anonymous
2b
Mertsj
  • Mertsj
Yes. So now put it all together. Look at the drawing.
Mertsj
  • Mertsj
And think of (b+c) as a unit.
Mertsj
  • Mertsj
|dw:1327550434478:dw|
anonymous
  • anonymous
|dw:1327550790530:dw|
anonymous
  • anonymous
Messed up on the drawing.
Mertsj
  • Mertsj
Do you see that (b+c)(3a) gives the first term and (b+c)(2b) gives the second term/
anonymous
  • anonymous
Yes.
Mertsj
  • Mertsj
And now it is factored because it is only one term
Mertsj
  • Mertsj
now if you have another problem like that, you should try it yourself. And if you don't have another one, you should go back and try to understand the others that you posted. It's called "factoring by grouping"
anonymous
  • anonymous
ok

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