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anonymous
 4 years ago
Factor this expression. Check by multiplying factors.
3ab+3ac+2b^2+2bc
anonymous
 4 years ago
Factor this expression. Check by multiplying factors. 3ab+3ac+2b^2+2bc

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Are you learning how to do these? You keep posting the same type of problem.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Take the first two terms: 3ab +3ac What do they have in common?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have Skype so we don't spam this feed?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok well they share "a"

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0What else do they share?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Good. so factor out 3a and tell me what you get

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Now take the last two terms which are 2b^+2bc What do they have in common?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327550017696:dw

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Factor out 2b. Not just 2

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0You said they have 2b in common and they do. So factor out 2b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327550097535:dw

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0I think that was my fault because I didn't get the exponent on the 2b^2

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0So you see that now we have 2 terms instead of 4?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0And what do those two terms have in common?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Do you see that they have (b+c) in common?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wow, backspace is retartded

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0What did you say they have in common/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0They're alreadty factored out. Is your backspace working? Mine won't work on this website but others it will.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0b+c times something equals the first term which is 3a(b+c)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Would you agree that (b+c)(3a )=3a(b+c)?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Now consider the second term 2b(b+c) (b+c) times something = 2b(b+c) What is it?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.02(b+c) does not equal 2b(b+c)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. So now put it all together. Look at the drawing.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0And think of (b+c) as a unit.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327550790530:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Messed up on the drawing.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Do you see that (b+c)(3a) gives the first term and (b+c)(2b) gives the second term/

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0And now it is factored because it is only one term

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0now if you have another problem like that, you should try it yourself. And if you don't have another one, you should go back and try to understand the others that you posted. It's called "factoring by grouping"
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