2 log base 3 sq.root. 27 ?!?!!?!?!?!!??!

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2 log base 3 sq.root. 27 ?!?!!?!?!?!!??!

Mathematics
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2 x logbase3(sqrt(27))?
\[2 \log _{3} \sqrt{27} \]
i dont understand it

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Other answers:

log base 3 of radical 27 is basicaly saying 3 to the what power = sqrt(27)
and i don't understand logs in general
but theres a 2 in front..
you multiply by two after you get the first part
its just multiplication in front
do u mind drawing this out ? sorry I'm really stupid :(
\[2 log_{3} (\sqrt {27})\] x=log y to the base b means b^x=y
we actually just did this stuff today and yesterday in math class
uh oh...maybe you're in my math class lol ...
and we have the property c log y= log y(^c)
lol, do you have algebra 2 im guessing?
nope...im still very confused about the 2 in front though...this whole thing makes no sense to me
the two in front is just multiplication, its like y = 2x, the two is multiplied
now \( 2 \log_{3} (\sqrt{27})\) \(\log_{3}{(\sqrt{27})}^2\) \(\log_{3} 27\) we know that 3^3=27 so it's \(\log_{3} 27=3\)
not sure what the guy above me is doing. How are you squaring the radical 27?
i am literally so confused
well, whatever he is doing is right.
the answer is 3
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Wow! I cannot believe I forgot that!
do either of you have Skype where you can help me with this? i am still very confused
how come when i check on my calc i get 4.95?

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