## anonymous 4 years ago 2 log base 3 sq.root. 27 ?!?!!?!?!?!!??!

1. anonymous

2 x logbase3(sqrt(27))?

2. anonymous

$2 \log _{3} \sqrt{27}$

3. anonymous

i dont understand it

4. anonymous

log base 3 of radical 27 is basicaly saying 3 to the what power = sqrt(27)

5. anonymous

and i don't understand logs in general

6. anonymous

but theres a 2 in front..

7. anonymous

you multiply by two after you get the first part

8. anonymous

its just multiplication in front

9. anonymous

do u mind drawing this out ? sorry I'm really stupid :(

10. ash2326

$2 log_{3} (\sqrt {27})$ x=log y to the base b means b^x=y

11. anonymous

we actually just did this stuff today and yesterday in math class

12. anonymous

uh oh...maybe you're in my math class lol ...

13. ash2326

and we have the property c log y= log y(^c)

14. anonymous

lol, do you have algebra 2 im guessing?

15. anonymous

nope...im still very confused about the 2 in front though...this whole thing makes no sense to me

16. anonymous

the two in front is just multiplication, its like y = 2x, the two is multiplied

17. ash2326

now $$2 \log_{3} (\sqrt{27})$$ $$\log_{3}{(\sqrt{27})}^2$$ $$\log_{3} 27$$ we know that 3^3=27 so it's $$\log_{3} 27=3$$

18. anonymous

not sure what the guy above me is doing. How are you squaring the radical 27?

19. anonymous

i am literally so confused

20. anonymous

well, whatever he is doing is right.

21. anonymous

22. ash2326

|dw:1327550653689:dw|

23. anonymous

Wow! I cannot believe I forgot that!

24. anonymous

do either of you have Skype where you can help me with this? i am still very confused

25. anonymous

how come when i check on my calc i get 4.95?