## anonymous 4 years ago Find the sum of the series: the problem looks like this, a 4 over the big E looking thing (which I can't show at this time) i = -1 below, 6i - 5 right next to it.

1. anonymous

$\sum_{}^{4}( 6i-5), i = \sqrt{-1}?$

2. anonymous

$\sum_{i=1}^{4}$ 6i - 5

3. anonymous

The 6i - 5 is right next to it not below it

4. anonymous

(6*1-5) +(6*2-5) +(6*3-5) +(6*4-5) = 40

5. anonymous

No wonder! I was looking everywhere on how to solve these type of problems. Thank you, so the answer comes out to be 40 correct?

6. anonymous

yup

7. anonymous

Thanks again :D

8. anonymous

the "big e" is called Sigma, remember sigma for SUM, have fun

9. anonymous

Sigma, got it