anonymous
  • anonymous
Find the sum of the series: the problem looks like this, a 4 over the big E looking thing (which I can't show at this time) i = -1 below, 6i - 5 right next to it.
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
\[\sum_{}^{4}( 6i-5), i = \sqrt{-1}?\]
anonymous
  • anonymous
\[\sum_{i=1}^{4}\] 6i - 5
anonymous
  • anonymous
The 6i - 5 is right next to it not below it

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anonymous
  • anonymous
(6*1-5) +(6*2-5) +(6*3-5) +(6*4-5) = 40
anonymous
  • anonymous
No wonder! I was looking everywhere on how to solve these type of problems. Thank you, so the answer comes out to be 40 correct?
anonymous
  • anonymous
yup
anonymous
  • anonymous
Thanks again :D
anonymous
  • anonymous
the "big e" is called Sigma, remember sigma for SUM, have fun
anonymous
  • anonymous
Sigma, got it

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