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anonymous
 4 years ago
Find ( f 1 )'( a )
anonymous
 4 years ago
Find ( f 1 )'( a )

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Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2first off...by inspection \[f^{1}(2)=0\]

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2then use \[\left[f^{1}\right]'(a)=\frac{1}{f'\left( f^{1}(a) \right)}\]

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2what I pointed out was just the first step in the problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ahh, see, these are the option I am given

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2ok...use the two posts of mine above and you should get the answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So if I did this right, 4/pi?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol, thats not what I'm going for

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that won't help much come actual class time

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2\[f'(x)=2x+\sec^2(\pi x/2)\pi/2\] \[\frac{1}{f'(f^{1}(2))}=\frac{1}{f'(0)}=\frac{1}{\pi/2}=\frac{2}{\pi}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh I see, you simplified f^1 and then you got f'

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2just combined my first two posts in this thread.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, I'm kind of a slow/visual learner... but I'll get it
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