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anonymous
 4 years ago
Hello Everyone!! In Physics I'm good with Diffrentiations and Integrations but I don't know when to apply them in a problem... Can Anyone give me that clear idea about that.. Please???
anonymous
 4 years ago
Hello Everyone!! In Physics I'm good with Diffrentiations and Integrations but I don't know when to apply them in a problem... Can Anyone give me that clear idea about that.. Please???

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What kind of calculus are you good at, exactly? Single variable? :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yea... I am..... But Please give me idea about when to appy these both things in a Physics problem!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How about this.... the acceleration of an object is the secondderivative of the position function with respect to time, i.e. \[ a(t) = x''(t) \] let's say a(t) = 0. What is x''(t)? You'll need two unknown constants for this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops, what is x(t), not x''(t) :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh my goodness I'm sorry. let's say a(t) = a0, a constant :) Can you integrate the equation twice to find the answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And to better answer your question... calculus is important in basic physics because you better understand concepts like velocity (which is the derivative of position wrt time). The really important applications of calculus to physics come when you learn multivariable calculus and vector calculus, which unfortunately will probably take quite a while but since our world is (ostensibly... ;) ) 3dimensional, singledimensional calculus applications are comparatively rare.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you have some conservative force, like gravity or the spring force or the electrostatic force, then \[ F = \frac{d}{dx} U\] where U is the associated potential energy.
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